Quote:
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Originally Posted by BMR777
You would have to get the info from both tables and store in variables. Then check if the money variable is greater than or equal to the currency in the users table. If it is, then deduct the currency and do the transaction. :)
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Yeah I tried to do that, but I can't get the code to replace the "name the adoptable" article content with "you can't afford this adoptable" if they don't have enough money.
It takes me to the name the adoptable page even if I in fact have less money than the adoptable cost.
This is the code I'm using:
PHP Code:
}
else if ($isloggedin == "yes" and $aID != ""){
//A Logged In user is adopting a new creature
//Check first that the creature does in fact exist...
//Get adoptable info
$query = "SELECT * FROM adoptables WHERE uid = '$aID'";
$result = @mysql_query($query);
$num = @mysql_numrows($result);
//Loop out code
$i=0;
while ($i < 1) {
$newID=@mysql_result($result,$i,"uid");
$name=@mysql_result($result,$i,"name");
$imageurl=@mysql_result($result,$i,"imageurl");
$cost=@mysql_result($result,$i,"description");
$i++;
}
//Get how much money you have
$query = "SELECT * FROM `users` WHERE `username` = '$username'";
$result = mysql_query($query);
$num = mysql_numrows($result);
//Loop out code
$i=0;
while ($i < 1) {
$money =@mysql_result($result,$i,"money");
$i++;
}
if($newID != $aID){
$stop = 1;
$article_title = "Error";
$article_date = date('Y-m-d');
$article_content = "This Digimon is not available for adoption. <a href='adopt.php'>Go back</a>.";
}
//Can the user afford the adoptable?
if($money < $cost){
$article_title = "Oops";
$article_date = date('Y-m-d');
$article_content = "You can't afford this Digimon.";
}
else {
//Creature is valid, let's adopt the sucker...
//Procedure for giving the user's adoptable a name
if($cname == "" and $flag !=12){
$article_title = "Adopt ".$name;
$article_date = date('Y-m-d');
$article_content = "<p align='left'>You are about to adopt ".$name.". </p>
<p align='left'><img src='".$imageurl."' border='0'></a> </p>
<p align='left'>You may give your new Digimon a nickname. His or her name can contain letters, numbers and spaces.</p>
<form name='form1' method='get' action='adopt.php'>
<p>
<input name='aID' type='hidden' id='aID' value = '".$aID."'>
Nickname
<input name='cname' type='text' id='cname' size=20 maxlength='20'>
<input name='flag' type='hidden' id='flag' value = '12'>
</p>
<p>
<input type='submit' name='Submit' value='Adopt!'>
</p>
</form>";
}
}
}
else{
Here are what the tables being referenced look like:
What is the problem?