Quote:
Originally Posted by draugluin
PHP Code:
$gender = new TCell($adopt->getGender("gui"));
if($currentlevel() == "0" $gender = "Egg");
but it won't work.
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It won't work for many reasons.
1) The if works like this:
PHP Code:
if(condition)
{
do this;
}
2) $currentlevel is a variable, not a function (when you do this something() or something($stuff) or something($stuff, $stuff2) are functions).
3) "0" is a string, you probably want an integer, which is just 0.
4) $currentlevel even as a variable won't work, it's an empty variable. You must have meant $adopt->getCurrentLevel() which is a function that returns the current level of the object $adopt.
5) And this:
PHP Code:
$gender = new TCell($adopt->getGender("gui"))
Gender is a TCell and below it you are saying it's a string ("Egg"). buildRow only accepts TCells. What you have to do is modify the
getGender function so it outputs what you want (either images or strings). That function is associated with $adopt. So you have to see what the variable $adopt is.
PHP Code:
$adopt = new OwnedAdoptable($aid);
You can see here, $adopt is an object/instance of the class OwnedAdoptable. That means that function is in the class_ownedadoptable file. In that file, you can see you have this variable visible to every function of that class:
PHP Code:
protected $currentlevel;
Which can be used with $this->currentlevel.
Then go to the function
PHP Code:
public function getGender($fetchMode = "")
And insert your condition there
PHP Code:
if($this->currentlevel == 0)
{
return "Egg";
}
for example
(this in 1.3.3, not sure how if the newest version changed a lot...)